Checking Voltage Drop while Supplying 6A Current

[mares0909]

Homework Statement

You would like to check if the battery voltage drops while it is supplying a current of 6A. You use a voltmeter designed to measure voltages up to 20V and having a resistance of 50,000 Ohms.
See attachment****

This connection is in series so V= I (R1+R2)
V / (R1+R2) = I
12 / (2+ 50000) = I
2.39E-4 = I

How much current (in A) would flow through the headlight for Circuit b?

The connection is in parallel so Req = (1/ R1 + 1/R2)
Req = (1/2 + 1/50000) = .50002

I = V / R
I = 12 / .50002
I= 23.99

Homework Equations

I want to check if what I have done is right.

The Attempt at a Solution

Is right bellow the questions.

Thanks

 

[montoyas7940]

You have your formula for Req wrong.

It should be 1/Req= (1/R1 + 1/R2)

So, Req = 1.99992.

 

[Moetasim]

for providing your equations and calculations. It appears that you have approached the problem correctly and your calculations are accurate. To confirm your results, you may want to double check your calculations and make sure you have accounted for all variables and units correctly. Additionally, you may want to consider conducting a physical experiment to measure the voltage drop and current flow in the circuit to validate your calculations. Overall, your approach and results seem sound and in line with the goal of checking for voltage drop while supplying a current of 6A. Good job!