- #1
arpitm08
- 50
- 0
Homework Statement
Are there positive integers m and n so that
n = sqrt(m+sqrt(m+sqrt(m+...sqrt(m))))
where there are 2008 square root signs.
2. The attempt at a solution
n^2=m+sqrt(m+sqrt(m+sqrt(m+...sqrt(m))))...with 2007 square roots.
Idk where to go from here. If there were infinite roots, then it would be a lot easier to do.
Any suggestions would be helpful. Thanks.