- #1
mertymertcan
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Hello guys, I'm new here. i was working on a mathematical methods in physics book and there is a part that i don't understand. so i want to ask if anyone knows... while finding a second solution for bessel diff. eq.(for m=0) the book used wronskian method. in the method there is J^2 bin the denominator. so it becomes J^-2 and the series is made such that
{1 - (x^2)/4 + (x^4)/64 - (x^6)/2304 + ... }^-2 = {1 + (x^2)/2 + (x^6)/32 + ...}
the part that i didnt understand how can someone conver minus 2 power into right hand side:S. please help me, is there a general formula for this?
{1 - (x^2)/4 + (x^4)/64 - (x^6)/2304 + ... }^-2 = {1 + (x^2)/2 + (x^6)/32 + ...}
the part that i didnt understand how can someone conver minus 2 power into right hand side:S. please help me, is there a general formula for this?