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A ball of radius 11 has a round hole of radius 8 drilled through its center. Find the volume of the resulting solid
here's what i done:
y = sqrt(11^2-x^2)
y = 8 about x-axis
[tex]\int pi*(8)^2 - pi*(8-sqrt(11^2-x^2))[/tex]
this is where I am stuck at, no clue if my setup is even correct. What would the bounds be and is my setup correct?
here's what i done:
y = sqrt(11^2-x^2)
y = 8 about x-axis
[tex]\int pi*(8)^2 - pi*(8-sqrt(11^2-x^2))[/tex]
this is where I am stuck at, no clue if my setup is even correct. What would the bounds be and is my setup correct?