- #1
IntuitioN
- 20
- 0
I believe that a scintillator converts xray photons into visible photons through the process of exciting electrons, then allowing it to fall to ground state.
My q is: shouldn't the energy of the photon released be the same as the photon energy that is used to excite the electron?
Just on that matter, does a photon energy HAVE to correspond exactly to the different electron energy shells in an atom for the photon to be absorbed?(eg if n=0 is -26eV and n=1 is -14eV then what happens if a 13eV photon comes along. Would it be absorbed?)
My q is: shouldn't the energy of the photon released be the same as the photon energy that is used to excite the electron?
Just on that matter, does a photon energy HAVE to correspond exactly to the different electron energy shells in an atom for the photon to be absorbed?(eg if n=0 is -26eV and n=1 is -14eV then what happens if a 13eV photon comes along. Would it be absorbed?)