Charge on point charge to create a spark

In summary, the question asks for the minimum charge needed to cause a breakdown of air and create a spark when a free electron is at a distance of 1.1cm from the point charge. The previous parts of the problem provided values for acceleration, force, and electric field, but these are not relevant to this part of the problem. The breakdown field strength is needed to find the minimum charge, which can be calculated using the equation E = k*q/r^2.
  • #1
chicagobears34
37
0

Homework Statement


Suppose a free electron in air is 1.1cm away from a point charge. What minimum charge must this point charge have to cause a breakdown of the air and create a spark?

I already have the Electric field and force, which I solved to be
E=7.2x10^6 N/C
F=1.2x10^-12 N

Homework Equations


F=(k*q1*q2)/r^2
f=Eq


The Attempt at a Solution


I tried using F=kq1q2 / r^2 and plugging in .011m in as r and then using q1=q2=charge of electron.
Then I did F=Eq and solved for q but i did not get the correct answer.
How should I be approaching this problem?
 
Physics news on Phys.org
  • #2
Well, what type of course is this? Electromagnetism or quantum mechanics? I think there are several ways to confront this problem, but it kinda depends on which course it is. Besides a free electron in air is kinda wrong.

The air between the electron and the charge represents some potential energy barrier. The point charge needs to have an energy large enough to move the electron 1.1 cm.

Now I don't understand how you calculated the electric field, though. It seems you need to use Coulombs law, which includes the charge of the point charge as well?

You should use the electrostatic potential energy to solve this, I think.
 
  • #3
hjelmgart said:
Well, what type of course is this? Electromagnetism or quantum mechanics? I think there are several ways to confront this problem, but it kinda depends on which course it is. Besides a free electron in air is kinda wrong.

The air between the electron and the charge represents some potential energy barrier. The point charge needs to have an energy large enough to move the electron 1.1 cm.

Now I don't understand how you calculated the electric field, though. It seems you need to use Coulombs law, which includes the charge of the point charge as well?

You should use the electrostatic potential energy to solve this, I think.

This class is just physics II and should just be a Coulomb's law problem, but I'm not sure what other ways to approach the problem other than the way I already tried
 
  • #4
I don't know how you arrived at
E=7.2x10^6 N/C
The field will depend on the magnitude of the point charge.
Presumably the point charge is positive. On the face of it, it's just a question of whether the field exceeds the breakdown strength of dry air (3.3*106 N/C). But that's for rounded surfaces, so I don't know how it applies here.
hjelmgart said:
The point charge needs to have an energy large enough to move the electron 1.1 cm.
There is no minimum field for that, the electron will surely drift into the +ve point charge. The question is whether the field strength is sufficient to break down the air dielectric, generating a cascade of electrons long before the free electron can travel the distance.
 
  • #5
this was a 4part question and the previous parts solved for the acceleration, force, and electric field.
The parts usually needed variables from the previous part to solve the answer. I got the field and force right and I figure they might need to be used to solve for the charge needed to spark, which was why I included them.
 
  • #6
chicagobears34 said:
this was a 4part question and the previous parts solved for the acceleration, force, and electric field.
The parts usually needed variables from the previous part to solve the answer. I got the field and force right and I figure they might need to be used to solve for the charge needed to spark, which was why I included them.
But this part asks you to find the value of the charge that will have a certain consequence, and the strength of the field will depend on that charge, so whatever field you previously calculated cannot be relevant.
Maybe you should post all the parts.
 
  • #7
haruspex said:
But this part asks you to find the value of the charge that will have a certain consequence, and the strength of the field will depend on that charge, so whatever field you previously calculated cannot be relevant.
Maybe you should post all the parts.

Part A:
The average distance an electron travels between collisions is 2.0μm . What acceleration must an electron have to gain 2.3×10^−18J of kinetic energy in this distance?
a=1.3x10^8 m/s^2

Part B:What force must act on an electron to give it the acceleration found in part A?
F=1.2x10^-12 N

Part C: What strength electric field will exert this much force on an electron? This is the breakdown field strength. Note: The measured breakdown field strength is a little less than your calculated value because our model of the process is a bit too simple. Even so, your calculated value is close.
E=7.2x10^6 N/C
 
  • #8
chicagobears34 said:
Part A:
The average distance an electron travels between collisions is 2.0μm . What acceleration must an electron have to gain 2.3×10^−18J of kinetic energy in this distance?
a=1.3x10^8 m/s^2

Part B:What force must act on an electron to give it the acceleration found in part A?
F=1.2x10^-12 N

Part C: What strength electric field will exert this much force on an electron? This is the breakdown field strength. Note: The measured breakdown field strength is a little less than your calculated value because our model of the process is a bit too simple. Even so, your calculated value is close.
E=7.2x10^6 N/C
OK, that makes it clearer. So the field you calculated is the field you need to generate from the point charge at a source of electrons to generate a spark. So, what point charge will produce this field at the given distance?
 
  • #9
Do I maybe set Kqq/ r^2 = Eq and solve for the q? We never covered the material in class yet, but the homework was assigned. Not exactly sure what other equations relate r with q other than kqq/r^2
 
  • #10
chicagobears34 said:
Do I maybe set Kqq/ r^2 = Eq and solve for the q? We never covered the material in class yet, but the homework was assigned. Not exactly sure what other equations relate r with q other than kqq/r^2
The charge of the electron is not relevant. If you have a point charge q, what is the field strength at distance r from it?
 
  • #11
oh I found one equation E=kQ/d^2
could that be it?
 
  • #12
chicagobears34 said:
oh I found one equation E=kQ/d^2
could that be it?
That's the one.
 
  • Like
Likes 1 person

1. What is a point charge?

A point charge is a theoretical concept in physics where all of the electric charge is concentrated at a single point in space. It is used as a simplification in mathematical models to describe the behavior of electric fields.

2. How is a spark created from a point charge?

A spark is created when there is a high enough potential difference between a point charge and its surroundings, causing an electric discharge or breakdown of air molecules. This results in a flow of electrons and the release of energy in the form of light and heat.

3. What factors affect the strength of a spark created by a point charge?

The strength of a spark created by a point charge depends on the magnitude of the charge, the distance between the point charge and its surroundings, and the dielectric strength of the medium between them.

4. Can a point charge create a spark in a vacuum?

No, a spark cannot be created by a point charge in a vacuum because there are no air molecules present to undergo the electric discharge.

5. What safety precautions should be taken when working with point charges and sparks?

When working with point charges and sparks, it is important to wear proper protective gear and work in a well-ventilated area. Make sure to handle high voltage equipment with caution and avoid contact with the point charge to reduce the risk of electric shock.

Similar threads

  • Introductory Physics Homework Help
Replies
2
Views
160
  • Introductory Physics Homework Help
Replies
3
Views
1K
  • Introductory Physics Homework Help
Replies
8
Views
2K
  • Introductory Physics Homework Help
Replies
4
Views
1K
  • Introductory Physics Homework Help
Replies
9
Views
3K
  • Introductory Physics Homework Help
Replies
10
Views
5K
  • Introductory Physics Homework Help
Replies
2
Views
1K
  • Introductory Physics Homework Help
Replies
9
Views
1K
  • Introductory Physics Homework Help
Replies
11
Views
675
  • Introductory Physics Homework Help
Replies
5
Views
12K
Back
Top