
#1
Feb2014, 02:54 PM

PF Gold
P: 11,058

An event has an 8% chance to occur per try. How would I calculate the chance of the event occurring at least once after 3 tries?




#2
Feb2014, 03:00 PM

P: 754

Is the probability in one trial independent of the actual results in the others?
If so, can you write a formula for the event to not occur at all in three tries? 



#3
Feb2014, 03:05 PM

P: 334

So, you want $$1 0.92^3$$ 



#4
Feb2014, 03:38 PM

Mentor
P: 11,255

Probability Question
To gain some insight into this problem, try the following bruteforce method. List all the possible outcomes for the set of three tries:
1=no, 2=no, 3=no : probability = 0.92 * 0.92 * 0.92 = … 1=yes, 2=no, 3=no : probability = 0.08 * 0.92 * 0.92 = … etc. Enumerate all the outcomes (how many of them are there?), calculate the probability for each one, and add up the ones that meet your criterion. 


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