omega of the second hand??

ehabmozart

Consider a second hand in the watch. What is the constqant angular velocity.
Logicaly, i would say it travels through 1 rev in 1 min so, it is 2∏/60
However, if we look it on the other way, it has angular acceleration
so theta= (w node + w final)/2 * t gives 2∏/30 .. Where is my mistake??

Doc Al

Quote by ehabmozart

Consider a second hand in the watch. What is the constqant angular velocity.
Logicaly, i would say it travels through 1 rev in 1 min so, it is 2∏/60

OK.

However, if we look it on the other way, it has angular acceleration

What other way? The angular velocity is constant.

so theta= (w node + w final)/2 * t gives 2∏/30 .. Where is my mistake??

What are you solving for? Using this you'll find an angular displacement of 2π radians in 60 seconds.

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ehabmozart	omega of the second hand?? Tweet Consider a second hand in the watch. What is the constqant angular velocity. Logicaly, i would say it travels through 1 rev in 1 min so, it is 2∏/60 However, if we look it on the other way, it has angular acceleration so theta= (w node + w final)/2 * t gives 2∏/30 .. Where is my mistake??