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Rosengrip
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Homework Statement
To rods, each with mass 0.3 kg and length 0.2 m, are welded together at one of their ends, so they form an L-shaped frame.
A ball with mass 0.3 kg and with speed 5 m/s hits one of the rods at its end at an angle of 0 degrees (so ball speed vector is perpendicular to one of the rods and parallel to the other) and rebounds (elastic collision).
Image represents the event:
[PLAIN]http://www.shrani.si/f/0/Dw/12MBWrLL/okvir.jpg
What's the speed of center of mass of frame and ball after the collision?
What's the angular speed of frame after collision?
Homework Equations
I=(1/12)ml2
Moment of inertia equations, mechanical energy equations, linear momentum equations
The Attempt at a Solution
Firstly I calculated the position of center of mass (COM from now on)and moment of inertia of frame if it's spinning around it.
If I put the center of coordinate system in the welding point, the COM is at coordinates (-0.05, -0.05) (point T on the picture).
Using parallel axis theorem I get the moment to be I=(5/12)ml2 (m=0.3 kg, l=0.2m). I=0.005 kgm2
Because the collision is elastic, linear momentum, mechanical energy and angular momentum of ball and frame combined stay the same.
I figured because the ball doesn't strike at an angle perpendicular to the vector pointing from COM to the strike point, we get 2 sets of equations.
1 component of ball speed vector (Vx) moves and rotates the frame (the one perpendicular to vector from COM to impact point).
1 component of ball speed vector (Vy) only moves the frame (parallel to the vector).
[PLAIN]http://www.shrani.si/f/I/FW/migS8fu/okvir.jpg
Let the component of speed vector perpendicular to vector from COM to impact point be Vx, the one which is parallel Vy.
m= ball mass = 0.3 kg
M= frame mass = 0.6 kg
Vx = ball speed x component before collision
Vy = ball speed y component before collision
Vx1 = ball speed x component after collision
Ux1 = frame speed x component after collision
Vy1 = ball speed y component after collision
Uy1 = frame speed y component after collision
I =f rame moment of inertia
w = angular speed of frame
d = distance between COM and impact point
Set of equations for Vx:
m(Vx) = -m(Vx1) + M(Ux1) -linear momentum
m(Vx) = -m(Vx1)d + Iw - angular momentum
(1/2)m(Vx)2=(1/2)m(Vx1)2+(1/2)M(Ux1)2+(1/2)Iw2 - mechanical energy (kinetic and rotational energy)
Set of equations for Vy:
m(Vy) = -m(Vy1) + M(Uy1) -linear momentum
(1/2)m(Vy)2=(1/2)m(Vy1)2+(1/2)M(Uy1)2 - mechanical energy (kinetic and rotational energy)
5 equations, 5 unknown variables (Vx1, Vy1, Ux1, Uy2, w). Threw the whole mess into Mathematica and I got some results.
The thing is, I'm not sure if this is the correct way since I'm new to this field. Any info on this would be greatly appreciated.
If there's any info missing, please tell me :)
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