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roadrally2
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Homework Statement
let r(t) (a<t<b) be a smooth vector valued function. suppose that the nonzero vector n is perpendicular to r'(t) for all values of t. Prove that the curve with parametrization r(t) lies in a plane
Homework Equations
The Attempt at a Solution
i know this has somethign to do with cross product. infact i know that the cross product of n x r'(t) will give me a third vector which will define the plane which r(t) lies in, but I don't know how to show a proof of this.
Thanks for your help or advice