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In summary, the conversation discusses a problem involving a disk with a radius of 0.05m being placed on a conveyor belt. The disk is at rest and the coefficient of kinetic friction between the disk and the belt is 0.2. The questions ask for the acceleration and angular acceleration of the disk, as well as equations and diagrams to determine the angular acceleration while slipping occurs. The formula for angular acceleration is tau = I * alpha, where tau is torque, I is moment of inertia, and alpha is angular acceleration. Another formula used is (1/r)(Vbelt/dt).
  • #1
foxandthehen
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0
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The axis of a disk with radius of 0.05m is fitted into a slot that forms an angle of 30degs with the vertical axis. The disk is at rest when it is placed in contact with a convayor belt moving at contsant speed. The coefficent of kenetic friction between the disk and the belt is 0.2 and there is no bearing friction.

a) Express the acceleration of the center of mass of the body, and its angular acceleration

b) Draw a free body diagram showing the applie forces and the eqivalent force diagram showing the vectror 'ma' or its conponents and 'Ia'

c) Write the three equations of motion and use them to determine the angular acceleration of the disk while slipping occurs.

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HELP! Where should I start? Any help and advice would be very much appreciated.
 
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  • #2
Well, you're being asked for angular acceleration. What formula do you know for that?

That's right... tau = I * alpha, in other words, alpha = tau / I, where alpha is the angular acceleration, tau is the torque, and I is the moment of inertia. Does that get you started?
 
  • #3
Hi! Thanks for the answer! I managed to do and hand it in yesterday and it was really quite simple in the end, think I just had a mental block about it! lol.
oh and I used Angular acceleration = (1/r)(Vbelt/dt) :D
 

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