- #1
indigojoker
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a parallel plate capacitor is charged by a battery and then disconnected from the battery. the separation between the plates is doubled...
the E-field stays the same since charge is constant
the voltage doubles since V=Ed
the energy doubles since U=0.5QV
I was wondering, where does this extra energy come from?
does total energy increase?
the E-field stays the same since charge is constant
the voltage doubles since V=Ed
the energy doubles since U=0.5QV
I was wondering, where does this extra energy come from?
does total energy increase?