- #1
hemetite
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Qn. A simple pendulum has a length of 3.00m. Det the change in it period if it is taken from a point where g=9.80ms2 to a higher elevation where the acceleration due to gravity decreases to 9.79ms2.
i cannot seem to start the question and a bit unsure here...
here is what i get...
Formula to use:
T = 2 pie sqrt L/g
i dun think the answer is just (T=2pie sqrt L/9.80) - (T=2pie sqrt L/9.70) right?
What i know, is that when the g start to reduce is at the point when it is starting going in the opposite direction, away from the equilibirium.(lowest point)
Please help to get me..i am stuck here...
i cannot seem to start the question and a bit unsure here...
here is what i get...
Formula to use:
T = 2 pie sqrt L/g
i dun think the answer is just (T=2pie sqrt L/9.80) - (T=2pie sqrt L/9.70) right?
What i know, is that when the g start to reduce is at the point when it is starting going in the opposite direction, away from the equilibirium.(lowest point)
Please help to get me..i am stuck here...