- #1
Phoenixtears
- 83
- 0
Homework Statement
The coefficient of kinetic friction between the m = 2.6 kg block in Figure P8.35 and the table is 0.28. What is the acceleration of the 2.6 kg block? (The image is attached)
______m/s2
Homework Equations
Fk= (Mu)(N)
2nd Law statements
The Attempt at a Solution
I began by drawing three force diagrams, one for each block. Using the 2.6 and 3 blocks I wrote out 2nd law statements (because the block is shifting right), and substituted in variables for the friction forece equation:
Ca= T- Cg
Ba= T- Fk
Fk=(Mu)(Bg)... (According to my force diagrams , normal force equals weight force)
Then I sovled for T on the first equation. Substituting that in for T in the second, and replacing the Fk with the other equation:
Ba= Ca+ Cg- (Mu)(Bg)
I then solved for a. After plugging in all the numbers, I got a very high number as my a. Near 55, if I recall. What exactly did I do wrong?