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mithanon
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Homework Statement
A neon atom (m = 20.0 u) makes a perfectly elastic collision with another atom at rest. After the impact, the neon atom travels away at a 57.9° angle from its original direction and the unknown atom travels away at a -45.4° angle. What is the mass (in u) of the unknown atom? [Hint: You can use the law of sines.]
variables
m = neon = 20 u
M = mass of unknown
[tex]\theta[/tex] = 57.9°
[tex]\phi[/tex] = 45.4°
v = initial velocity of neon
v' = final velocity of neon
V = final velocity of unknown
Homework Equations
I've set up conservation of momentum equations for both directions, and the energy equation, but I'm stuck with more unknowns than equations
The Attempt at a Solution
mv2=mv'2+MV2
mv = mv'cos[tex]\theta[/tex] + MVcos[tex]\phi[/tex]
0 = mv'sin[tex]\theta[/tex] - MVsin[tex]\phi[/tex]
using a momentum vector sum diagram and law of sines? I got
mv/sin(180-[tex]\theta[/tex]-[tex]\phi[/tex])=mv'/sin([tex]\phi[/tex])
not sure how that helps but I guess I can then express v' in terms of v, eliminating one variable
no idea where to go from here