Partial Fractions: Solving 4/((s^2) + 4)(s-1)(s+3)

In summary, using partial fractions in an equation can simplify the expression and make it easier to solve by breaking the fraction into smaller, simpler fractions. To find the partial fraction decomposition, the denominator is factored into irreducible factors and a system of equations is set up to solve for the unknown coefficients. However, partial fractions can only be used for values of s that are not equal to the roots of the denominator, and it is limited to rational functions with a polynomial denominator. It can also be applied to other types of mathematical problems, such as integrals and differential equations, to simplify complex functions.
  • #1
sara_87
763
0

Homework Statement



we have 4/((s^2) + 4)(s-1)(s+3)

Homework Equations





The Attempt at a Solution



dividing it up do we get:

A/((s^2) + 4) + B/(s-1) + C/(s+3) = 4

or is it

(As + B)/((s^2) + 4) + C/(s-1) + D/(s+3) = 4
 
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  • #2
The second one. Since the denominator s2+ 4 is quadratic the numerator may be As+ B.
 
  • #3
cheers!
 

What is the purpose of using partial fractions in this equation?

The purpose of using partial fractions in this equation is to simplify the expression and make it easier to solve. By breaking the fraction into smaller, simpler fractions, we can use algebraic methods to solve for the individual values of the variables.

How do you find the partial fraction decomposition of this equation?

To find the partial fraction decomposition of this equation, we first factor the denominator into its irreducible factors. Then, we set up a system of equations using the coefficients of each term in the numerator and equating them to the corresponding coefficients in the partial fraction decomposition. Finally, we solve for the unknown coefficients by using algebraic methods.

Can we use partial fractions to solve for all values of s?

No, we can only use partial fractions to solve for the values of s that are not equal to the roots of the denominator. In this equation, the roots of the denominator are s=1 and s=-3, so we cannot use partial fractions to solve for these values of s.

What are the limitations of using partial fractions to solve this equation?

The limitations of using partial fractions to solve this equation are that it only works for rational functions with a polynomial denominator and that it can only be used for values of s that are not equal to the roots of the denominator.

Can partial fractions be applied to other types of mathematical problems?

Yes, partial fractions can also be applied to other types of mathematical problems, such as integrals and differential equations. In these cases, the purpose is to break down a complex function into simpler fractions that can be integrated or differentiated more easily.

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