Apatite Homework Help - Find P in 1150 kg of Apatite

  • Thread starter chawki
  • Start date
  • Tags
    Homework
In summary, the conversation revolved around finding the amount of pure phosphorus (P) in 1150 kg of apatite, which is used to manufacture fertilizer. The formula weight and molar mass of apatite were discussed, as well as the empirical formula and the number of moles of phosphorus per mole of apatite. Ultimately, the correct calculation was found to be 211.866 kg of pure phosphorus. The conversation ended with a reminder to watch significant figures and a note of appreciation for the help.
  • #1
chawki
506
0

Homework Statement


Apatite (Ca5(PO4)3F) is used to manufacture fertilizer.

Homework Equations


How many kilograms of pure phosphorus (P) is included in 1150 kg of apatite?



The Attempt at a Solution


How we solve this, tell me only first step...
we can't even use the composition percentage law :grumpy:
 
Physics news on Phys.org
  • #2


Start with the forumla weight of apatite. Convert to moles.

Can you take it from there?
 
  • #3


can you please tell me how to find the formula weight?
i have learned chemistry ages ago..and it was in french..

maybe you meant the molar mass ? if it's that, then it is 504.31g/mol
504.31 = 1150000/n
n= 1150000/504.31
n= 2280.34mol
 
Last edited:
  • #4


Right, that's how many moles of apatite. How many moles of phosphorous per mole of apatite?
 
  • #5


That's where I'm stuck
 
  • #6


Just look at the empirical formula. You do this part by inspection... nothing to calculate.
 
  • #7


1mole
 
  • #8


So if you were given 1 mole of Ca5(PO4)3F, you would get only one mole of P out of it?
 
  • #9


i'm not sure, I'm confused
 
  • #10


mp/30.97 = 1150000/504.31
mp= 7062.22g
 
  • #11


AxBy gives you x moles of A and y moles of B per mole of AxBy.

How about the moles of P in one mole of Ca5(PO4)3F?
 
  • #12


Three
 
  • #13


chemisttree said:
So if you were given 1 mole of Ca5(PO4)3F, you would get only one mole of P out of it?

Not necessarly i think
 
  • #14


chawki said:
mp/30.97 = 1150000/504.31
mp= 7062.22g

70622.23
 
  • #15


Please tell me if I'm right
 
  • #16


No. You have still ignored fact that there are three moles of P per apatite molecule.
 
  • #17


mp/3*30.97 = 1150000/504.31
mp= 211866.709g
mp=211.866Kg
 
  • #18


Please reply to my posts!
 
  • #19


We are not your private tutorial service, aren't we?

Watch significant figures.
 
  • #20


No, You are not. and i want to say that i appreciate having time for posting and replying.
God bless you all.
 

1. What is Apatite?

Apatite is a mineral that is commonly found in sedimentary, igneous, and metamorphic rocks. It is composed of calcium phosphate and can range in color from white to various shades of green and blue.

2. Why is P important in Apatite?

P is the chemical symbol for phosphorus, an essential nutrient for plants and animals. Apatite is a major source of phosphorus, which is used in fertilizers and other industrial products.

3. How do I find P in Apatite?

To find the amount of P in Apatite, you will need to know the weight of the Apatite sample and the percentage of phosphorus present in the mineral. Multiply the weight of the sample by the percentage of phosphorus (expressed as a decimal) to get the amount of P in the Apatite.

4. What if I don't know the percentage of P in Apatite?

If you do not know the percentage of phosphorus in the Apatite sample, you can try to find this information through a mineral identification guide or by consulting a geologist. Alternatively, you could perform a chemical analysis of the sample to determine the percentage of P present.

5. How do I convert the P in Apatite to other units?

If you need to convert the amount of P in Apatite to other units, such as grams or moles, you will need to know the molar mass of phosphorus (30.97 g/mol). Multiply the amount of P in Apatite by this molar mass to convert it to grams, or divide by the molar mass to convert it to moles.

Similar threads

  • Biology and Chemistry Homework Help
Replies
2
Views
2K
  • Biology and Chemistry Homework Help
Replies
6
Views
2K
  • Biology and Chemistry Homework Help
Replies
4
Views
4K
  • Biology and Chemistry Homework Help
Replies
1
Views
3K
  • Biology and Chemistry Homework Help
Replies
5
Views
2K
  • Quantum Interpretations and Foundations
2
Replies
38
Views
4K
  • Introductory Physics Homework Help
Replies
3
Views
936
  • Calculus and Beyond Homework Help
Replies
3
Views
1K
  • Biology and Chemistry Homework Help
Replies
5
Views
1K
  • Introductory Physics Homework Help
Replies
13
Views
5K
Back
Top