- #1
KMjuniormint5
- 67
- 0
The question is:
A particle moves horizontally in uniform circular motion, over a horizontal xy plane. At one instant, it moves through the point at coordinates (3.00 m, 3.00 m) with a velocity of -5.00 m/s and an acceleration of +10.0 m/s2. What are the coordinates of the center of the circular path?
I know centripical acceleration is a = (v^2)/r
I know:
ax = 0 m/s^2
ay = 10 m/s^2
and . . .
vx = -5 m/s
vy = 0 m/s
where do i go from here?
A particle moves horizontally in uniform circular motion, over a horizontal xy plane. At one instant, it moves through the point at coordinates (3.00 m, 3.00 m) with a velocity of -5.00 m/s and an acceleration of +10.0 m/s2. What are the coordinates of the center of the circular path?
I know centripical acceleration is a = (v^2)/r
I know:
ax = 0 m/s^2
ay = 10 m/s^2
and . . .
vx = -5 m/s
vy = 0 m/s
where do i go from here?