Mass loss in relation to radius of a star

In summary, Reimers' law is a popular mass loss equation for stars, developed by D. Reimers. It is given by the equation dM/dt = -(4x10^-13) * η(L/(gR)) solar masses per year, where η is a free parameter close to unity and L, g, and R are the luminosity, surface gravity, and radius of the star, respectively. It may seem counterintuitive that as the radius of the star increases, the amount of mass lost decreases. However, when looking at Reimers' law more closely, it is evident that the surface gravity is a factor in the equation, meaning that as the radius increases, the surface gravity decreases and results in
  • #1
Markus0003000
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One of the most popular mass loss equations of a star, developed by D. Reimers, is given by:
dM/dt = -(4x10^-13) * η(L/(gR)) solar masses per year

Where η is a free parameter close to unity and L, g, and R are the luminosity of the star, surface gravity of the star, and the radius of the star, respectively.

What I am curious about is that when R increases, the amount of mass lost decreases. This seems counterintuitive, as when the radius increases, the density will decrease and the pull of gravitational energy will decrease so you would expect there to be greater mass loss.

Is there a qualitative reason why the star loses more mass as the radius decreases?
 
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  • #2
Markus0003000 said:
Is there a qualitative reason why the star loses more mass as the radius decreases?
In a sense it doesn't. Look at Reimers' law more closely:
$$\frac{dM}{dt} = -4\cdot10^{-13} \, \eta \frac {L_{\ast}} {gR_{\ast}}$$
That g in the denominator is surface gravity relative to that of the Sun: ##g=M_{\ast}/R_{\ast}^2##. Thus another way to write Reimers' law is
$$\frac{dM}{dt} = -4\cdot10^{-13} \, \eta \frac {L_{\ast}R_{\ast}} {M_{\ast}}$$
 

What is mass loss in relation to the radius of a star?

Mass loss in relation to the radius of a star refers to the gradual decrease in a star's mass as it expands in size. This phenomenon is commonly observed in stars nearing the end of their lives.

What causes mass loss in stars?

Mass loss in stars is primarily caused by the intense radiation and stellar winds that are produced during the later stages of a star's life. This radiation and wind can carry away particles from the star's outer layers, resulting in a decrease in mass.

How does the radius of a star affect its mass loss?

The radius of a star is directly related to its mass loss. As a star's radius increases, its surface area also increases, allowing for more stellar winds and radiation to escape and carry away particles, resulting in a greater mass loss.

Can mass loss in a star lead to its death?

Yes, mass loss can play a significant role in the death of a star. As a star loses mass, it also loses energy and can no longer sustain the fusion reactions that keep it shining. This can ultimately lead to the star's death, either in the form of a supernova or a planetary nebula.

How do scientists study mass loss in stars?

Scientists study mass loss in stars through various methods, including spectroscopy and observations of stellar winds. They also use computer models and simulations to better understand how mass loss affects a star's evolution and eventual death.

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