- #1
Abigale
- 56
- 0
Hello,
I am thinking for some hours about the commutation of the field-Operator/(annihilation-Operator): [itex]\Psi[/itex] and the vector-potential: [itex]\vec{A(\vec{r})}[/itex].
I have noticed in my lecture notes that [itex]\vec{A(\vec{r})}\Psi = \Psi\vec{A(\vec{r})}[/itex].
But I don't understand why they commute?
Thank u!
Abby
I am thinking for some hours about the commutation of the field-Operator/(annihilation-Operator): [itex]\Psi[/itex] and the vector-potential: [itex]\vec{A(\vec{r})}[/itex].
I have noticed in my lecture notes that [itex]\vec{A(\vec{r})}\Psi = \Psi\vec{A(\vec{r})}[/itex].
But I don't understand why they commute?
Thank u!
Abby