Question about Bragg diffraction

In summary, diffraction occurs when waves travel through an object and create a pattern of waves that arent directly visible. Bragg equation must be satisfied and h,k,l must be of certain combination in order for diffraction to occur. Higher order diffraction occurs when waves travel through an object and create a pattern of waves that are visible. The families of possible crystal planes increase with the number of reflections. When looking at families of possible crystal planes, the simple cubic (100) includes every plane parallel to this surface; the (200) includes every other such plane; the (600) includes every 6th plane - these higher orders cover the
  • #1
kelvin490
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For diffraction to occur in crystal, Bragg equation must be satisfied and h,k,l must be of certain combination. I would like to ask

1. How to distinguish a second order diffraction of (100) and first order diffraction of (200)? (they occurs at the same angle.)

2. How can a (200) plane diffraction of simple cubic possible? It seems that there is no atom from this plane because atom only at the four corners of a unit cell.
 
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  • #2
Some may say that the (200) diffraction is actually the second order (100), but it seems that the (200) plane simply doesn't exist. FCC and BCC also have this problem.
 
  • #3
The Bragg reflections for first order: λ=2 d sin(Θ);
for higher orders (=n) we have: nλ=2 d sin(Θ).

The diffraction angle increases with the increase in n; thus the (222) reflection appears further out than the (111) reflection - however, in general it will be much weaker.


When you look at the families of possible crystal planes the simple cubic (100) includes every plane parallel to this surface; the (200) includes every other such plane; the (600) includes every 6th plane - these higher orders cover the cases where the intervening planes are "missed" by the incoming radiation; this must be possible for the Bragg equation to work: the model is based on "partially reflecting" surfaces, which are the planes.

In reciprocal space these planes are closer and closer together by the reciprocal ratio: the (200) family is twice as close together as the (100) family.

Kittel's "Introduction to Solid State Physics" goes over most everything you would need to know in an easy to understand fashion.
 
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Thanks. I understand that every higher order (n) diffraction of (hkl) can be represented by (nh nk nl) diffraction. The existence of (nh nk nl) diffraction can also be proved even the limitation of h,k,l combination are considered (e.g. h+k+l must be even for BCC).

What I still wondering is that how can we tell whether a plane exist? Does it necessarily have a set of atoms whose centers lying on that plane (like (100) in simple cubic) or if diffraction can occur then the plane exist even there is no atoms lying on that plane (like (200) in simple cubic)?
 
  • #5
Do you mean the selection rules, or the physical presence of the plane?

For the (100) plane you can consider just the unit cell; for the (200) plane you simply stack two unit cells, etc.

You won't run out of planes until you run out of atoms in the crystal ... there are usually more than enough, even in tiny crystallites. However, most of the beam energy is diffracted away by the lower order planes, so the higher orders become fainter and fainter - it often requires a time exposure to make them visible.
 
  • #6
UltrafastPED said:
Do you mean the selection rules, or the physical presence of the plane?

For the (100) plane you can consider just the unit cell; for the (200) plane you simply stack two unit cells, etc.

If we stack two unit cells the interplanar distance is still that of (100) for simple cubic. The (200) plane has half the interplanar distance of (100), but there is no atom lying on (200) because the atoms only locate on the eight corner of unit cell. So I wonder how the (200) plane can cause diffraction.
 
  • #7
kelvin490 said:
If we stack two unit cells the interplanar distance is still that of (100) for simple cubic. The (200) plane has half the interplanar distance of (100), but there is no atom lying on (200) because the atoms only locate on the eight corner of unit cell. So I wonder how the (200) plane can cause diffraction.

The distance between (200) planes is 1/2 that of the (100) planes only in the reciprocal space; in the configuration space of the crystal they are twice as far apart as the (100) planes.

And they are easy to find because they only require two layers of the crystal.

You would do well to read a textbook like Kittel in order to improve your visualization; it does take a while to get used to crystallography and Miller indices and Bragg diffraction.

Perhaps this: http://www.slideshare.net/joserabelo/x-ray-diffraction-basics
 

1. What is Bragg diffraction and how does it work?

Bragg diffraction is a phenomenon in which X-rays or other electromagnetic radiation are scattered in a regular pattern by atoms in a crystal lattice. This occurs when the wavelength of the radiation is similar to the spacing between the lattice planes of the crystal. The scattered waves interfere constructively, resulting in a diffraction pattern that can be used to determine the atomic structure of the crystal.

2. What is the Bragg equation and how is it used in Bragg diffraction?

The Bragg equation, nλ = 2d sinθ, relates the wavelength of the incident radiation (λ), the spacing between the crystal lattice planes (d), and the angle at which the diffraction occurs (θ). It is used to calculate the angle at which the diffraction peaks will appear, which can then be used to determine the spacing between the lattice planes and ultimately the atomic structure of the crystal.

3. What is the difference between Bragg diffraction and other types of diffraction?

Bragg diffraction is specific to the scattering of X-rays or other electromagnetic radiation by a crystal lattice. Other types of diffraction, such as Fresnel diffraction and Fraunhofer diffraction, involve the scattering of light by obstacles or apertures, rather than a crystal lattice.

4. How is Bragg diffraction used in scientific research?

Bragg diffraction is a widely used technique in materials science and crystallography to determine the atomic structure of crystals. It is also used in the field of X-ray crystallography to determine the structure of proteins and other biological molecules. Additionally, Bragg diffraction is used in the study of thin films and surface structures, as well as in the analysis of crystal defects and imperfections.

5. Are there any limitations to Bragg diffraction?

While Bragg diffraction is a powerful and widely used technique, it does have limitations. It requires a single crystal sample, as polycrystalline samples will produce overlapping diffraction patterns. It is also limited to crystals with well-defined lattice planes, and the analysis can be complicated by the presence of impurities or defects in the crystal. Additionally, Bragg diffraction is best suited for studying crystalline solids and is less effective for amorphous materials.

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