Algebra Question: Finding Distance When a Train and Car Meet

  • Thread starter mikefitz
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    Algebra
In summary, the train and car both leave the station at different speeds. After two hours, the car catches up to the train and travels a total of 7 miles in doing so. The question asks for the distance the car travels, not the time it takes to catch the train.
  • #1
mikefitz
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Train leaves station going 50MPH
Car leaves station going 70MPH - 2 hours later

How far til car catches train?

This should be so simple, here is what I've done:

d=50t
d=70(t-2)

50t=70(t-2)
50t=70t-140
140=20t

I get t=7 miles for my final answer, but according to the book this is wrong. Why?
 
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  • #2
try it this way: when the car starts the train is 100 miles away. the car makes up ground at 20 miles/hour (70-50)... how many hours does it take to catch the train... how many miles did the car go in that time.
 
  • #3
How did you get miles from that? If
d=50mph*t hours
d=70mph*(t-2)hours

50mph*t hours=70mph*(t-2)hours
50mph*t hours=70mph*t hours-140 miles
140 miles=20mph*t hours
140miles/20mph = t hours
7 hours = t hours
 
  • #4
I think the problem is that you've solved for t when the question asks you to solve for d, the distance.

Of course you can now just put t back into one of the equations.
 

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