Need some help with the hall effect.

[aesopsowner]

Hey there.
Trying to figure out how to find a hall voltage across a ribbon. I'm given J, B, and some other factor: R-sub-h OHM*meter/tesla. (no clue what this is... )I'm also told to assume the charge carriers are e-'s. I understand that the hall effect is used to determine which charges are actually moving, but i can't really understand how the hall voltage is determined outside of V(hall) = q*width of ribbon*B.

I'm really not looking for an answer, but some general guidelines or tools that will help me solve the problem. Thanks in advance.

 

[Greg Bernhardt]

Hi there! The Hall voltage is determined by the Hall effect, which states that when an electric current passes through a conductor in the presence of a magnetic field, a potential difference is created across the conductor. In other words, the Hall voltage is the ratio between the electric current and the magnetic field. As for the R-sub-h OHM*meter/tesla, this is the Hall coefficient, which is used to calculate the Hall voltage. To find the Hall voltage, you need to multiply the Hall coefficient by the current, the width of the ribbon, and the magnetic field strength. Hope this helps!

 

[charng]

Sure, I can provide some guidance on how to approach this problem. The Hall effect is a phenomenon in which a magnetic field applied perpendicular to a current-carrying conductor will cause a voltage to develop across the conductor. This voltage is known as the Hall voltage and can be used to determine the type and density of charge carriers in the material.

To find the Hall voltage across a ribbon, you will need to use the equation you mentioned: V(hall) = q*width of ribbon*B. In this equation, q represents the charge of the carriers, which in this case are electrons (e-). The width of the ribbon is the distance between the two sides of the ribbon, and B is the strength of the magnetic field.

To find the value of q, you will need to use the other factor given to you, R-sub-h OHM*meter/tesla. This factor is known as the Hall coefficient and is a material property that relates the Hall voltage to the magnetic field and the current density (J). The equation for the Hall coefficient is R-sub-h = 1/nq, where n is the carrier density. So, to find q, you can rearrange this equation to q = 1/(n*R-sub-h).

Once you have found the value of q, you can plug it into the Hall voltage equation along with the other given values to find the Hall voltage. Keep in mind that the Hall voltage will be a negative value if the charge carriers are electrons, as they will experience a force in the opposite direction of the current due to the Lorentz force.

I hope this helps guide you in solving the problem. If you have any further questions, please don't hesitate to ask. Good luck!