Wattage Rating

gneill

Yes. You should keep a couple of extra decimal places in your intermediate values, and always carry the units, so 8.047 kΩ would be a better value
You need to be careful about the decimal place, so if you specify your resistance in kΩ your result will be in milliamps (mA). If you convert to Ohms first, the result will be in amps. It's probably simpler if you work in base units at this stage, so convert resistances to Ohms for your calculations.

nyxsilverjk

Ok, I think I had an awesome Ah-hah! moment and I think I can finish the problem. When I do can I give my answers and then you can give me a yes or no to if they're right?

gneill

No promises about yes/no; it might be better to give a hint or two If I'm not online, no doubt someone else will be happy to have a look.

nyxsilverjk

It's ok if you can't tell me. But here's my answers going in order from left to right the last one is the bottom left resistor. 19.28 W , 8.64 W , 1.59 W , 1.08 W , 41.18 W

gneill

Your values are all three orders of magnitude too high, so it looks as though you used kΩ as though they were Ω. Remember, a kΩ is 1000Ω. Also, the values are close but are not precise. Did you keep enough digits in intermediate values?

It would help if you would show one or two of your calculations to confirm your methodology.

nyxsilverjk

I went back and did the entire thing and kept my placing past the thousandths. I also did convert my k ohms and m amps. Then two other students and I compared answers and discussed them, we all came to the same consensus. I'm going to my teacher tomorrow during study hall to confirm some minor questions on syntax.

Thank you so much for helping me with this problem, it's greatly appreciated!