lijoeman said:Homework Statement
A 160 g ball attached to a spring with spring constant 2.8 N/m oscillates horizontally on a frictionless table. Its velocity is 20 cm/s when x_0 = 4.5 cm.
a_max = _______ cm/s^2
2. The attempt at a solution
Using F = ma and F = kx
kx = ma
a = kx/m
Substituting the appropriate values
a = (2.8)(4.5)/(.16) = 78.75 cm/s^2
Am I missing something here?
That gives you the acceleration at some particular value of x. It will only be a_max when x = x_max.lijoeman said:Using F = ma and F = kx
kx = ma
a = kx/m
Acceleration is the rate of change of an object's velocity over time. It is a measure of how quickly an object's speed is changing.
The maximum acceleration of a ball depends on various factors such as the initial velocity, mass, and the force acting on it. However, in a vacuum, the maximum acceleration of a ball due to gravity is approximately 9.8 m/s².
The maximum acceleration of an object can be calculated by dividing the change in its velocity by the time it takes to make that change. This can be represented by the formula: a = (vf - vi)/t, where a is acceleration, vf is the final velocity, vi is the initial velocity, and t is the time taken.
Yes, the shape of a ball can affect its maximum acceleration. For instance, a smooth and round ball may have less air resistance and therefore experience a greater acceleration compared to a ball with a rough surface.
Air resistance can reduce the maximum acceleration of a ball by exerting a force in the opposite direction of its motion. This force can depend on factors such as the shape, size, and speed of the ball, as well as the density and viscosity of the air.