Calculating Resultant Force on a Moving Blade Impinged by a Jet of Water

In summary, a jet of water with a diameter of 70mm and a velocity of 25m/s is deflected through 130o by a stationary blade. The resultant force on the blade, in magnitude and direction, can be calculated using the impulse-momentum equation. If the blade has a velocity of 5m/s in the same direction as the jet and the jet loses 20% of its velocity due to friction, the force on the moving blade can be recalculated. It is assumed that the density of water is 1000kg/m3. Appropriate illustrations should be included to show the solutions for both (a) and (b).
  • #1
lennyp1ke
4
0
A jet of water 70mm in diameter moving with a velocity of 25m/s impinges tangentially on a stationary blade which deflects the jet through 130o.
(a) Find the resultant force on the blade, in magnitude and direction.
(b) If the blade has a velocity of 5m/s in the same direction as the jet and the jet loses 20% of its velocity due to friction, recalculate the force on the moving vane.
Assume density of water = 1000kg/m3.

Your solutions to both (a) and (b) to include appropriate illustrations
can some one please help or give me an idiots example of how to get started on this , I am not good at word to show my working out i have no answer as i can't work out ( u ) uk way of working out equation
thanks
if i could just get a good pionter i should be able to do it myself using my notes guys thanks
 
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  • #2
Think impulse-momentum equation: ∫Fdt = Δp
where
F = force
t = time
p = momentum.

(Vectors are in bold)
 
  • #3
thanks man well appreciated, ill give it a go , then well see if it looks right thanks
 

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