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Zero point energy and IR spectroscopy |
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| Jul12-12, 05:52 AM | #1 |
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Zero point energy and IR spectroscopy
I made some frequency calculations in Gaussian (using various method/basis set combos) and I have to find which method/basis set combo is the most accurate by comparing the results to literature values. I got the calculated wavenumbers along with their intensities but my professor tells me I need to be corrected for zero point energy. I struggled in his spectroscopy class last year so I don't know what zero point energy is, let alone how to correct these values for it. If I just google zero point energy, I'm a visual thinker so quantum chemistry isn't my strongest area. Can anyone explain how this zero point energy relates to IR spectra? I'm googling zero-point energy so I'll learn as much about it as I can but I suspect it will be a long time before I find an explanation as to how it relates to IR absorbances.
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| Jul12-12, 07:50 AM | #2 |
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Sounds like you are expected to do a literature search...? We probably should not help you there since diving in to the lit is how you learn how to deal with it. If we just throw up some papers that would defeat the purpose. http://www.calphysics.org/zpe.html In IR spectroscopy, though, it is common to model the systems being observed as harmonic oscillators. In a quantum harmonic oscillator, the minimum energy is not zero: this is the zero-point energy for the system. Here's your visual: ![]() from http://131.104.156.23/Lectures/CHEM_...l_spectroscopy (scroll down to "zero point energy".) Notice there is a non-zero minimum energy at [itex]E=h\nu_0/2[/itex]? |
| Jul12-12, 05:52 PM | #3 |
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E_n=hf(n+1/2) where E_n is the energy of the level, n is the excitation number of the level (n=0,1,2,3,...), h is Plancks constant, and f is the fundamental frequency of that energy level. The above formula is used a lot in IR spectroscopy, both absorption spectroscopy and Raman spectroscopy. The term 1/2 is the contribution of zero point energy. |
| Jul15-12, 10:53 AM | #4 |
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Zero point energy and IR spectroscopyThanks for the diagram but I'm not entirely sure what it represents. I'm guessing v=0 is the ground state vibrational frequency. So lets use Cr(CO)6 as an example. The C-O bond produces an intense peak at around 2000 cm-1. If I'm not mistaken, 2000 cm-1 corresponds to the energy differece between v=0 and v=1 for the C-O bond. I'm still trying to get my head around what exactly zero point energy is. In the article you linked, it says zero-point is the energy of a system when T=0. So lets say my system is a can of butane and the temperature is absolute zero. Zero-point energy is the energy thats left over? As for harmonic oscillators, I'll use a spring with a metal ball at the end of it as an example of a macroscopic harmonic (lets pretend its harmonic i.e. forget about gravity and air resistance etc.) oscillator. I can see that at the very moment the metal ball changes direction, its kinetic is zero but its potential energy is at its highest. How does this concept apply to a quantum harmonic oscillator? |
| Jul15-12, 11:12 AM | #5 |
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BTW, heres the output from one of my frequency calculations:
74.4629, 98.1250, 116.5055, 328.6017, 337.3187, 413.5514, 527.1941, 558.8680, 666.7709, 2157.3618, 2160.9906, 0.0000, 0.0000, 5.6900, 0.0000, 0.0000, 83.7658, 0.0000, 0.0000, 304.6480, 0.0000, 2480.6823 The first number is the wavenumber, the number below it is the intensity. As you can see, the most intense peak is the one at 2160.9906 cm-1, which has an intensity of 2480.6823. Thats clearly the C-O peak. I have about 30 output files which all contain a calculation for this carbonyl peak. I need to determine which calculation is the most accurate. Those calculations above were done by HCTH/6-311G. My professor tells me I need to correct these calculations for zero point energy before I can compare them to literature values so thats what I'm trying to figure out now. |
| Jul15-12, 12:20 PM | #6 |
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Why not just save yourself some effort, and ask your professor how to do the ZPE correction?
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| Jul15-12, 02:53 PM | #7 |
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| Jul15-12, 04:07 PM | #8 |
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Right - so I know what he means.
It turns out for various reasons, ab-initio calculations for vibrational frequencies (like you do in Gaussian) turn out to be slightly incorrect when compared with experiment. It's standard practice to simply multiply the calculated values by some empirical factor to correct the problem. I've been told that this factor (which depends on the particular method you use for your calculation) tends to be fairly universal across a large set of molecules. The factors can be looked up in the literature (experimental chemists use them all the time to analyze their IR spectra). Do you really understand what your project is? |
| Jul15-12, 05:10 PM | #9 |
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Ah right. The gaussian site:
http://www.gaussian.com/g_tech/g_ur/k_freq.htm gives the following correction factor: Zero-point correction= .023261 (Hartree/Particle) so I suppose thats all I need to use. You're last question: No, I don't really know what I'm supposed to be doing for this research project. I was new to Gaussian when I started so the terminology he was using had me baffled. I have a vague idea though. My professor is researching substituted octahedral chromium carbonyl complexes and the project he assigned me is to determine if any of the newer density functional methods are more effective at making calculations on octahedral carbonyl complexes than Hartree-Fock methods. I happen to be a programmer so I've been doing all kinds of side projects for him by programming scripts to extract data from the output files etc. but I think I'm pretty much finished this research project. |
| Jul15-12, 05:12 PM | #10 |
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While quantum chemistry isn't my strongest field, I'm glad I got this particular project because I finally got to implement my programming skills in chemistry. You'd be amazed at the power programming gives you when it comes to dealing with data outputted by Gaussian.
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| Jul15-12, 06:27 PM | #11 |
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I could be wrong, but I think the correction factor above is to the total energy.
I don't think the Gaussian output file has the correction factor you want in it. I take it you'll either need to look it up in the literature, or find out what the real IR spectra look like for the compounds in question to compare with your results. |
| Jul16-12, 05:54 PM | #12 |
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I have a literature value:
http://pubs.acs.org/doi/abs/10.1021/ja01593a008 the carbonyl peaks wavelength lands right on 5 microns which corresponds to 2000 cm-1. Any idea where I'd find a zero-point correction factor to apply to my calculations? Heres my lecturers original reply: |
| Jul16-12, 06:35 PM | #13 |
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The correction factor is empirical - you have to use experimental data to work it out.
Think of it as finding a systematic error in a measurement - only here it is in the calculation. The same correction factor should apply to every calculation - which tells you if the theory is good. |
| Jul17-12, 08:19 AM | #14 |
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Ah, I think I get it now. The experimental CO absorption for Cr(CO)6 is at 1988 cm-1 in alkane solvent. If I calculate its zero-point energy, then I can subtract it from 1988 cm-1 and get a Born-Oppenheimer approximation value. From those two values I can derive the correction factor. Have I got the right idea?
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| Jul17-12, 08:50 AM | #15 |
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