Is there a Doppler effect when sound source and object move at right angles?

In summary, the question "Is there a Doppler effect if a sound source and an object are moving at right angles?" is ambiguous and not clearly defined. If the objects are moving in different directions, there will most likely be a Doppler effect. However, if the objects are moving at a right angle with respect to each other, there will be no Doppler effect unless they pass through the axis of motion of the other object at one specific instant. The statement "moving at right angles" is not specific enough to determine the presence or absence of a Doppler effect.
  • #1
endeavor
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"Is there a Doppler effect if a sound source and an object are moving at right angles?"

I assume this means that both are moving away from a single point...
I thought there would be a Doppler effect because both objects are moving and therefore the sound produced has an effective longer wavelength.

However, the answer in the back of my book is a simple "no". What am I doing wrong?
 
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  • #2
It means that the source is moving sideways instead of towards or away from the observer. The sound source must be moving towards or away from you to have a Doppler effect. (Not so relativistically: Look up the "transverse Doppler effect" for light.)
 
  • #3
endeavor said:
"Is there a Doppler effect if a sound source and an object are moving at right angles?"
I think the problem is not stated very well. Just because the dot product of the two velocity vectors is zero, doesn't mean that the time derivative of the difference between their two position vectors is zero (which would have to be true for there to be no Doppler shift).

Take the case of a person riding up an outdoor elevator as a train goes by on the ground directly below him. Of course he will hear a Doppler shift up as the train approaches the spot on the ground below him, and a Doppler shift down after the train passes. If the problem wanted to have the answer be "no", then it should have constrained the question to the instant when one of the objects passes through the axis of motion of the other object.
 
  • #4
I agree with berkeman. In my mind, if two objects are closing in on one another or separating during a givin time period, then the doppler effect will be heard. If the two objects were moving at right angles such that the hypotenueuse of the triangle would stay a constant length (quarter quadrants of a circle??) then I think no.
 
  • #5
berkeman said:
If the problem wanted to have the answer be "no", then it should have constrained the question to the instant when one of the objects passes through the axis of motion of the other object.
Right. I should have made that clearer in my response. (And I agree that the problem is poorly stated.) Only at one instant will the Doppler effect be truly zero. (Good catch! :smile:)
 
  • #6
So my answer could be correct?

I'm not sure I understand your explanations 100%, but I think I get it. I'm only taking an introductory physics course so I haven't learned anything other than the source/observer moving away/toward each other; and I didn't learn about using vectors with the Doppler effect either.
 
  • #7
Given your perfectly reasonable interpretation of the ambiguous statement "moving at right angles" as meaning, say, that the source is moving east while the observer is moving north, then a Doppler effect will most likely be observed. (As berkeman explained.) The key is: Is the distance between observer and source changing? If yes, then there's a Doppler effect; if no, no Doppler effect. (If the source is moving towards the observer, the observed frequency is higher; if it is moving away, it's lower.)

What they probably meant to say was something like: "Is a Doppler effect observed if the source moves (with respect to the observer) at a right angle with respect to the line between source and observer?" In that case the answer is no.

I'm curious, what's the exact statement of the question in your book?
 
  • #8
Well the exact statement just happens to be almost the same, and is still ambiguous.
Is there a Doppler effect if a sound source and an observer are moving (a) with the same velocity or (b) at right angles? (c) What would be the effect if a moving source accelerated toward a stationary observer?

Even part (a) is ambiguous. However, I know they must mean that both the source and the observer are moving in the same direction with the same velocity, because the answer is no. For part c, the frequency would be increasing.
 
  • #9
Even part (a) is ambiguous.
Actually, the term "velocity" often denotes the velocity vector (as opposed to the scalar term "speed"), so in that sense, (a) isn't ambiguous. (c) works too, and I think we all agree that (b) is ambiguous. Maybe you'll get extra credit for pointing out why (b) is ambiguous...?
 
  • #10
berkeman said:
Actually, the term "velocity" often denotes the velocity vector (as opposed to the scalar term "speed"), so in that sense, (a) isn't ambiguous. (c) works too, and I think we all agree that (b) is ambiguous. Maybe you'll get extra credit for pointing out why (b) is ambiguous...?
Oh yeah, I was thinking about speed. Yeah, I'll see if I can get some extra credit :biggrin:
 

1. What is the Doppler effect?

The Doppler effect is the change in frequency or wavelength of a wave in relation to an observer who is moving relative to the source of the wave. It is commonly observed in sound waves, such as the change in pitch of a siren as an ambulance drives by, but it also applies to other types of waves, such as light.

2. How does the Doppler effect affect wavelengths?

The Doppler effect causes an increase or decrease in the wavelength of a wave depending on the relative motion of the observer and the source. If the observer is moving towards the source, the wavelength will appear shorter, and if the observer is moving away from the source, the wavelength will appear longer.

3. What is the formula for calculating the Doppler effect?

The formula for calculating the Doppler effect is:
fobs = fsource * (v +/- vobs) / (v +/- vsource)
Where fobs is the observed frequency, fsource is the frequency of the source, v is the speed of the wave, vobs is the velocity of the observer, and vsource is the velocity of the source. The +/- sign depends on whether the observer and source are moving towards or away from each other.

4. Can the Doppler effect be applied to any type of wave?

Yes, the Doppler effect can be applied to any type of wave, including sound, light, and water waves. However, it is most commonly observed in sound waves due to its impact on pitch.

5. How is the Doppler effect used in real life?

The Doppler effect has many practical applications in real life. It is used in radar technology to determine the speed and direction of moving objects, in medical ultrasound to measure blood flow in the body, and in astronomy to measure the distance and speed of stars and galaxies. It is also used in meteorology to track the movement of storms and in traffic control to monitor the speed of vehicles.

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