"Proof of a Formula for Differentiating x^p with Respect to y

In summary, the formula for differentiating x^p with respect to y is d(x^p)/dy = p*x^(p-1). This formula is derived using the power rule of differentiation, and can be applied for any value of p as long as it is a constant. It can be used in various situations, but has limitations as it can only be used for simple power functions and not more complex functions. Other rules and formulas must be used in those cases.
  • #1
hedlund
34
0
Let y = x^p where p is a natural number. Is it true that
[tex] \frac{dx^n}{d^ny} = \frac{p!}{(p-n)!} \cdot x^{p-n} [/tex] with the restriction that we define [tex] (-n)! \equiv \infty [/tex] for n=1,2,3... I found this formula and I believe that it is true if we define [tex] (-n)! [/tex] to equal [tex] \infty [/tex].
 
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  • #2
Your answer is correct, although you wrote the derivative upside down. The definition you used for (-n)! is the standard one.
 
  • #3


The formula provided is indeed correct, as long as we define (-n)! to equal infinity for all natural numbers n. This definition allows us to extend the factorial function to negative numbers, which is necessary for the formula to hold true.

To prove this formula, we can use the definition of the derivative as the limit of the difference quotient. Let's start by taking the derivative of y = x^p with respect to x:

\frac{dy}{dx} = p \cdot x^{p-1}

Next, we can rewrite this as:

\frac{dy}{dx} = \frac{p}{1} \cdot x^{p-1}

From this, we can see that the coefficient of x^{p-1} is p, which is the same as the coefficient in the formula provided. Now, let's take the nth derivative of y with respect to x:

\frac{d^n y}{dx^n} = \frac{p}{1} \cdot \frac{p-1}{2} \cdot \frac{p-2}{3} \cdot ... \cdot \frac{p-(n-1)}{n} \cdot x^{p-n}

We can rewrite this as:

\frac{d^n y}{dx^n} = \frac{p!}{(p-n)!} \cdot x^{p-n}

This matches the formula provided, but with one key difference - the restriction that (-n)! equals infinity for all natural numbers n. This is necessary because as n increases, the denominator in the expression for the nth derivative becomes larger and larger, approaching infinity. Therefore, we must define (-n)! to equal infinity in order for the formula to hold true for all values of n.

In conclusion, the formula \frac{dx^n}{d^ny} = \frac{p!}{(p-n)!} \cdot x^{p-n} is correct for y = x^p, as long as we define (-n)! to equal infinity for all natural numbers n. This formula can be useful in solving problems involving derivatives of functions with a variable exponent, such as x^p.
 

1. What is the formula for differentiating x^p with respect to y?

The formula for differentiating x^p with respect to y is: d(x^p)/dy = p*x^(p-1)

2. How is this formula derived?

This formula is derived using the power rule of differentiation, which states that the derivative of x^p is equal to p*x^(p-1). This rule can be applied to any power function, including x^p, by taking the power (p) and multiplying it by the coefficient of x (1 in this case).

3. Can this formula be used for any value of p?

Yes, this formula can be used for any value of p, as long as p is a constant. If p is a variable, then the formula would be different, as it would involve the chain rule.

4. Is this formula applicable in any situation?

Yes, this formula can be applied in many different situations, such as finding the derivative of a polynomial function, calculating the slope of a curve, or solving optimization problems.

5. Are there any limitations to this formula?

While this formula is a useful tool for finding derivatives, it does have its limitations. It can only be used for functions that can be written in the form of x^p, and it does not work for more complex functions such as trigonometric or exponential functions. In those cases, other rules and formulas must be used.

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