- #1
Torshi
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The van't Hoff factor for KCl is i= 1.85. What is the boiling point of a 0.50 m solution of KCl in water? For water, Kb = 0.51.
I have the equation which i believe is (Delta Tb)= Kb x m x i ??
m= molality... = .50 m
Kb is given 0.51
i is given 1.85
I have to have 5 sig figs and the answer i get is .47175, but that's not right supposedly. What I'm I doing wrong?
I have the equation which i believe is (Delta Tb)= Kb x m x i ??
m= molality... = .50 m
Kb is given 0.51
i is given 1.85
I have to have 5 sig figs and the answer i get is .47175, but that's not right supposedly. What I'm I doing wrong?