- #1
Fernandez
- 2
- 0
Homework Statement
Find the solution for y"+2y'+5y=(e^x)sinx
Homework Equations
The Attempt at a Solution
So far I think I've gotten the solution from the characteristic equation, but I'm having trouble with the particular solution.
For the characteristic equation solution:
y"+2y'+5y=0
r^2+2r+5=0
Using the quadratic formula r= -1(+/-)2i
So y=(e^-x)((C1)cos(2x)+(C2)sin(2x)
For the particular solution I think I'm assuming correctly that y=A(e^x)sin(2x)+B(e^x)cos(2x), or am I not catching a term that can be combined with the complementary solution? Or am I just using the wrong equation all together?