- #1
EvilBunny
- 39
- 0
Homework Statement
Let
arctan ([tex]\sqrt{3x^2 -1}[/tex])
then dy/dx
Well I know that the derivative of arctanx is
1/ 1 + x ² but when I got something other then simply x I don't know how to proceed
Inverse trigonometric functions are mathematical functions that perform the opposite operation of a regular trigonometric function. They are used to find the angle or side length of a right triangle when given the ratio of its sides.
The six inverse trigonometric functions are arc sine (sin⁻¹), arc cosine (cos⁻¹), arc tangent (tan⁻¹), arc cotangent (cot⁻¹), arc secant (sec⁻¹), and arc cosecant (csc⁻¹).
The derivative of an inverse trigonometric function can be found using the chain rule, where the derivative of the inverse function is multiplied by the derivative of the original function.
The derivative of inverse sine (sin⁻¹x) is equal to 1/√(1-x²).
Finding the derivative of an inverse trigonometric function can be useful in solving real-world problems involving angles or triangles, as well as in calculus and other advanced mathematical concepts.