- #1
DaDramaQueen
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1. Prove that
[tex](h\circ g)\circ f = h\circ (g\circ f)[/tex]
[tex]f:A\longmapsto B[/tex],
[tex]g:B\longmapsto C[/tex],
[tex]h:C\longmapsto D[/tex]
[tex](h\circ g)\circ f =\{(b,d):d=h(c)\}\circ f[/tex]
[tex]=\{(b,d):d=h(g(b))\}\circ f[/tex]
I reach there and get stuck to continue
[tex](h\circ g)\circ f = h\circ (g\circ f)[/tex]
Homework Equations
[tex]f:A\longmapsto B[/tex],
[tex]g:B\longmapsto C[/tex],
[tex]h:C\longmapsto D[/tex]
The Attempt at a Solution
[tex](h\circ g)\circ f =\{(b,d):d=h(c)\}\circ f[/tex]
[tex]=\{(b,d):d=h(g(b))\}\circ f[/tex]
I reach there and get stuck to continue
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