- #1
physics517
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Homework Statement
A mass m is resting at equilibrium suspended from a vertical spring of natural length L and spring constant K inside a box.
The box begins accelerating upward with acceleration a. How much closer does the equilibrium position of the mass move to the bottom of the box?
Homework Equations
f=kx
f=ma
The Attempt at a Solution
so this is my f=ma statement
kx-mg=ma
then i solved for x to get x= m(a+g) / k
but this answer is wrong and the correct answer is
ma / k