- #1
Norman
- 897
- 4
Hello all,
I have a fellow grad student who is convinced that the differential cross section:
[tex] \frac{d\sigma}{d\Omega}[/tex]
is truly a ratio of differentials. That is you have an infinitesimal cross section divided by an infinitesimal solid angle.
I contend that when we write
[tex] \frac{d\sigma}{d\Omega}[/tex]
we really mean
[tex] \sigma(\Omega) [/tex] and that we only call it the differential cross section because the integral of the differential cross section over the physical range of the variable gives the total cross section.
I stated this along with the fact that the total cross section is simply a number. You sample an event (lets say pp->pp is the event in question) at different energies and record the number of particles that come out of the reaction at the energy. This gives you a number.
The derivative of the number with respect to any variable is zero. So the differential cross section- is not the derivative of the cross section.
He contends this is not true because when you do the "experiment" you have a finite width detector and this smears out the solid angle so it is no longer an infinitesimal.
Can anyone find a very clear discussion somewhere about this fact? Or maybe present one? Or am I simply wrong and it truly can be thought of as a ratio of differentials?
Thanks,
Ryan
I have a fellow grad student who is convinced that the differential cross section:
[tex] \frac{d\sigma}{d\Omega}[/tex]
is truly a ratio of differentials. That is you have an infinitesimal cross section divided by an infinitesimal solid angle.
I contend that when we write
[tex] \frac{d\sigma}{d\Omega}[/tex]
we really mean
[tex] \sigma(\Omega) [/tex] and that we only call it the differential cross section because the integral of the differential cross section over the physical range of the variable gives the total cross section.
I stated this along with the fact that the total cross section is simply a number. You sample an event (lets say pp->pp is the event in question) at different energies and record the number of particles that come out of the reaction at the energy. This gives you a number.
The derivative of the number with respect to any variable is zero. So the differential cross section- is not the derivative of the cross section.
He contends this is not true because when you do the "experiment" you have a finite width detector and this smears out the solid angle so it is no longer an infinitesimal.
Can anyone find a very clear discussion somewhere about this fact? Or maybe present one? Or am I simply wrong and it truly can be thought of as a ratio of differentials?
Thanks,
Ryan