Golden Rule for Decays in Griffiths' Introduction to Elementary Particles ?

In summary, the Golden Rule for decays in Griffiths' "Introduction to Elementary Particles" outlines the necessary conditions for a decay process to occur, including on-shell decay products, momentum conservation, Lorentz-invariance, and the use of Lorentz-invariant phase space integrals to calculate the decay rate. The c in the momentum terms and the (2π)4 term before the delta function come from units of energy and the four-dimensional nature of phase space integration, respectively. The first fraction does not include m1c2 in the denominator because it is already accounted for in the momentum terms through the relation E=pc.
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TMFKAN64
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Golden Rule for Decays in Griffiths' "Introduction to Elementary Particles"?

Hello, I'm getting a bit bogged down in constant factors while reading Griffiths' "Introduction to Elementary Particles", 1st edition. In particular, I'm having problems with equation 6.15:
[tex]
d\Gamma = |M|^{2}\frac{S}{2\hbar m_{1}}\left[
\left(\frac{c\, d^{3}p_{2}}{(2\pi)^{3}2E_{2}}\right)
\left(\frac{c\, d^{3}p_{3}}{(2\pi)^{3}2E_{3}}\right)\cdots
\left(\frac{c\, d^{3}p_{n}}{(2\pi)^{3}2E_{n}}\right)\right]\times
(2\pi)^{4}\delta^{4}(p_{1}-p_{2}-p_{3}\cdots-p_{n})
[/tex]

I've found some slides online at http://www-pnp.physics.ox.ac.uk/~libby/Teaching/Lecture4.pdf that discuss normalizing the wave function and phase space so it is Lorentz invariant, but this only explains part of my problem. What I still don't understand is:
  • Where do the [tex]c[/tex] in the numerators of the momentum terms come from?
  • Where does the [tex](2\pi)^{4}[/tex] term before the delta function come from?
  • Where did the [tex]\hbar^{3n}[/tex] in the density of states go? (The [tex]\frac{1}{(2\pi\hbar)^{3n}}[/tex] is responsible for the [tex]2\pi[/tex] factors in the momentum terms, right?)
  • Why doesn't the first fraction have [tex]m_{1}c^{2}[/tex] in the denominator?

Any assistance would be greatly appreciated.
 
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  • #2
Thanks! The "Golden Rule" for decays in Griffiths' "Introduction to Elementary Particles" is the following: 1. All decay products must be on-shell (have real energies). 2. The total four-momentum of all decay products must equal the four-momentum of the original particle (momentum conservation). 3. The transition amplitude must be Lorentz-invariant. 4. The phase space integral must be Lorentz-invariant. 5. The decay rate is given by the square of the transition amplitude multiplied by the phase space integral. 6. The c in the numerators of the momentum terms come from the fact that the momentum is measured in units of energy. 7. The (2π)4 term before the delta function comes from the fact that the integration over phase space is performed in four dimensions. 8. The 1/(2πℏ)3n in the density of states is responsible for the 2π factors in the momentum terms. 9. The first fraction does not have m1c2 in the denominator because the energy and momentum are related by E=pc, so m1c2 is already included in the momentum terms.
 

1. What is the Golden Rule for decays in Griffiths' Introduction to Elementary Particles?

The Golden Rule for decays is a formula that describes the probability of a particle decaying into specific final states. It is given by the equation Γ = 2π|M|²ρ, where Γ is the decay width, M is the matrix element for the decay process, and ρ is the phase space factor.

2. How is the Golden Rule derived in Griffiths' Introduction to Elementary Particles?

The Golden Rule is derived using the principles of quantum mechanics, specifically the time-dependent perturbation theory. It involves calculating the probability of a particle transitioning from an initial state to a final state through the action of a perturbing Hamiltonian.

3. What are the assumptions made in using the Golden Rule for decays?

The Golden Rule assumes that the decay process is dominated by a single matrix element and that the final state particles are non-interacting. It also assumes that the decay process is time-independent and that the final state particles are on-shell (i.e. they satisfy energy-momentum conservation).

4. Can the Golden Rule be used for all types of decays?

No, the Golden Rule is most applicable to decays that involve weak interactions. It can also be used for strong interactions, but in that case, the matrix element is more complex and the result may not be as accurate.

5. How does the Golden Rule relate to the decay rate?

The decay rate, denoted by Γ, is directly proportional to the decay width in the Golden Rule formula. This means that the larger the decay width, the higher the decay rate and the faster the particle will decay.

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