Calculating Flux Through Cylinder w/ Vector Field

In summary, the task is to find the flux of a vector field through the surface of a closed cylinder with radius and height c, centered on the z-axis with base on the xy-plane. The suggested solution is to use the divergence theorem, where the integral over the surface is equal to the integral of the divergence over the cylinder. For a vector field of (6x, 6y), the divergence is found to be 12 and multiplied by the volume of the cylinder, which is πc^3, resulting in a flux of 12πc^3. When asked to find the limit, the answer is also 12.
  • #1
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Homework Statement



Find the flux of the vector field through the surface of the closed cylinder of radius c and height c, centered on the z-axis with base on the xy-plane.

Homework Equations





The Attempt at a Solution



Can I just use the divergence theorem here? Find the divergence of the vector field and then multiply it by the volume of the cylinder?
 
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  • #2
Yes, you can use the divergence theorem but the is not "find the divergence of the vector field and then multiply it by the volume of the cylinder" unless the divergence is a constant. By the divergence theorem, the integral over the surface is the integral of the divergence over the cylinder.
 
  • #3
so if it's not a constant then I should integrate it right
 
  • #4
Yes!
 
  • #5
if I have:

[tex] \vec{F} = 6x\vec{i} + 6y\vec{j} [/tex]

then according to greens theorem this is 0 right? so therefore the flux is 0 as well?
 
  • #6
bump!
 
  • #7
No, it's not zero. You don't use green's theorem in this problem. The theorem you have to use is Gauss' divergence theorem. First find the divergence of F. What is the divergence of (6x, 6y)?
 
  • #8
it's just 12... and then multiply it by the volume right, which is [tex] \pi c^3 [/tex] so it's [tex]12\pi c^3[/tex]
 
  • #9
That's right. Now just use the divergence theorem. The flux out of the cylinder is ∫(div F)dV over the volume of the cylinder.
 
  • #11
What limit?
 
  • #12
read my attachment above.. I don't understand the question it self
 
  • #13
Yes, the answer is 12.
 
  • #14
so the limit and the flux density are both 12?
 
  • #15
If by 'flux density' you mean 'divergence', then yes.
 
  • #16
yea flux density is divergence
 

1. How do you calculate the flux through a cylinder with a vector field?

To calculate the flux through a cylinder with a vector field, you will need to use the formula Flux = ∫∫S F · dS, where F is the vector field and dS is the surface element. You will also need to parameterize the surface of the cylinder and determine the limits of integration.

2. What is the significance of calculating flux through a cylinder with a vector field?

Calculating the flux through a cylinder with a vector field allows us to understand the flow of a vector field through a given surface, in this case a cylinder. This can help us understand the behavior of the vector field and its impact on the environment or objects within the cylinder.

3. How do you determine the direction of the flux through a cylinder with a vector field?

The direction of the flux through a cylinder with a vector field can be determined by using the right-hand rule. Place your right hand fingers in the direction of the vector field and curl them towards the surface. The direction of your thumb will indicate the direction of the flux.

4. Can the flux through a cylinder with a vector field be negative?

Yes, the flux through a cylinder with a vector field can be negative. This indicates that the flow of the vector field is entering the cylinder rather than leaving it. However, the magnitude of the flux is what is important in determining the strength of the vector field.

5. Are there any real-world applications of calculating flux through a cylinder with a vector field?

Yes, there are many real-world applications of calculating flux through a cylinder with a vector field. For example, it can be used in fluid dynamics to understand the flow of air or water through pipes or channels. It can also be used in electromagnetism to analyze the magnetic field around a conductor or solenoid. Additionally, it can be used in meteorology to study the movement of air masses in the atmosphere.

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