How much energy is released as 1kg of hydrogen is consumed?

[frozen7]

15. The following fusion reaction takes place in the sun and furnishes much of its energy:
, where is a positron. How much energy is released as 1kg of hydrogen is consumed? The masses of 1H, 4He, and are, respectively, 1.007825, 4.002604, and 0.000549 u, where atomic electrons are included in the first two values

I do it by finding the difference of mass between the parent nucleus and daughter nucleus and multiply with 931.5MeV. The answer I got is 25.708MeV,which is actually different with the given answer, 6 x 10^14 J. Why?
Which part I have done wrongly?

 

[Mattara]

This might give you a clue:

$$^{1}_{1}H+^{1}_{1}H\xrightarrow~^{2}_{1}H + p$$

Try and use standard value for isotopes not the average.

 

[quicknote]

I cannot provide a definitive answer without more information about the context and source of the given answer. However, I can provide an explanation for the discrepancy between your calculated value and the given value.

Firstly, it is important to note that the given value of 6 x 10^14 J is the total energy released from the fusion of 1 kg of hydrogen. This includes the energy released from all the fusion reactions that take place in the sun, not just the specific reaction provided in the question. So, it is possible that the given value takes into account other fusion reactions that also contribute to the sun's energy output.

Secondly, the calculation you have done assumes a perfect conversion of mass into energy, which is not always the case. In reality, some of the mass is converted into other forms of energy, such as kinetic energy of the particles involved in the reaction. This may account for the difference between your calculated value and the given value.

Additionally, the given value may have been calculated using a different method or taking into account other factors that were not included in your calculation. It is also possible that there was a mistake in the given value.

In conclusion, it is important to consider the context and sources of information when comparing values and to keep in mind that there may be other factors at play that can affect the final result.