
#1
Mar813, 03:08 PM

P: 21

The square of the four vector potential.
[itex](\phi,A)^2=\phi ^2  A^2[/itex] What's the physical meaning of this lorentz invariant? 



#2
Mar813, 08:49 PM

Mentor
P: 16,485

If the invariant is timelike then it would be the scalar potential in a frame where the vector position was 0, and if the invariant is spacelike then it would be the magnitude of the vector potential in a frame where the scalar potential is 0. However, unless you are using the Lorentz gauge your gauge condition is frame variant so interpreting it becomes a little strange.



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