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When does a ball enter free fall? |
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| Nov25-12, 06:57 PM | #1 |
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When does a ball enter free fall?
So in a physics lab, we threw a ball upwards and recorded its acceleration.
If you look at the graph there is actually a period of time where it goes from positive acceleration to -9.8 m/s2. But how is that possible? Before I let go of the ball, it experiences a positive acceleration because I am applying a force causing the net force to be up, but as soon as I let go, the only force acting on it is gravity, so wouldn't the acceleration have to jump from some positive number to -g? |
| Nov25-12, 09:16 PM | #2 |
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| Nov26-12, 09:06 AM | #3 |
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| Nov26-12, 10:57 AM | #4 |
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When does a ball enter free fall? |
| Nov26-12, 11:15 AM | #5 |
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The acceleration does not have to be a continuous function of time. It can change discontinuously. Only the velocity and displacement need to be continuous functions of time.
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| Nov26-12, 11:51 AM | #6 |
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I would imagine that as the ball leaves the hand, the upward force on it goes to zero very quickly, but not instantaneously - the hand isn't rigid.
So, the acceleration will change very quickly from positive to negative, but not instantaneously. |
| Nov26-12, 12:30 PM | #7 |
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| Nov26-12, 12:54 PM | #8 |
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If you model the hand as a rigid body, then I can see that the force from it would drop to zero instantly giving a discontinuous acceleration.
But this is a consequence of our idealised model. I don't see how the force/acceleration could be discontinuous in a real situation. |
| Nov26-12, 12:57 PM | #9 |
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| Nov26-12, 02:01 PM | #10 |
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| Nov26-12, 02:46 PM | #11 |
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| Nov26-12, 03:34 PM | #12 |
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So at what acceleration does the ball enter free fall? My TA said when the acceleration becomes negative. Maybe because at zero acceleration there is no net force?
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| Nov26-12, 03:43 PM | #13 |
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At what acceleration does the ball enter free fall? That's easy: by definition, free fall occurs when only gravity is affecting it, and you already know that answer. |
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