
#1
Sep3013, 12:02 AM

P: 87

can u describe this motion? how is x > 0 at E? how can we tell the sign of x from the graph?




#2
Sep3013, 03:03 AM

Sci Advisor
PF Gold
P: 1,114

This looks like a harmonic oscillator centered on ##x=0##. In that case, ##a=0## corresponds to ##x=0## and the acceleration is pointing to the left (##a <0##) when the particle is right of ##x=0##. Therefore ##a < 0## means ##x > 0##, which is the case for ##t_\mathrm{E}##.




#3
Sep3013, 03:05 AM

Homework
Sci Advisor
HW Helper
Thanks ∞
PF Gold
P: 11,120

You cannot actually tell the absolute position of the object just from looking at the vt graph alone  you can only tell how it changes position. 


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