- #1
island-boy
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Fact 1: we know that a closed subspace of a Hilbert Space is also a Hilbert Space.
Fact 2: we know that the Sobolev Space [tex]H^{1}[/tex] is a Hlbert space.
How do I show that the space [tex]V:=\{v \in H^{1}, v(1) = 0\}[/tex] is a Hilbert space?
Is V automatically a closed subspace of [tex]H^{1}[/tex]? How do I show this? cause I can't see how it is so.
Alternatively, is there a way to prove that the space [tex]V:=\{v \in H^{1}, v(1) = 0\}[/tex] is a Hilbert space, without using facts 1 and 2? that is how do I show that V is complete? (it is automatically an inner product space because it is in [tex]H^{1}[/tex]).
Thanks.
Fact 2: we know that the Sobolev Space [tex]H^{1}[/tex] is a Hlbert space.
How do I show that the space [tex]V:=\{v \in H^{1}, v(1) = 0\}[/tex] is a Hilbert space?
Is V automatically a closed subspace of [tex]H^{1}[/tex]? How do I show this? cause I can't see how it is so.
Alternatively, is there a way to prove that the space [tex]V:=\{v \in H^{1}, v(1) = 0\}[/tex] is a Hilbert space, without using facts 1 and 2? that is how do I show that V is complete? (it is automatically an inner product space because it is in [tex]H^{1}[/tex]).
Thanks.
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