What is the critical number of the function f(x)= x^3 + 3x^2-24x?

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In summary, the function f(X) has a critical number at x=3 and the derivative of the function f'(X) is -17.
  • #1
afcwestwarrior
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find the critical number of the function

f(X)= x^3 + 3x^2-24x

f'(X)= 3x^2 + 6x -24

what do i do, next i found the derivative of the function
 
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  • #2
Well, perhaps you should find out either where the derivative equals 23.67, -17 or perhaps some more important value, say 0.
 
  • #3
ok so its supposed to equal zero as the definition states for critical numbers,

so i just plug in any numbers in the x's
 
  • #4
afcwestwarrior said:
so i just plug in any numbers in the x's

Eeh??
Do you know what an equation is, and how to solve it??
 
  • #5
i think ido, can u show me an example
 
  • #6
yes i know what an equation is, but how do i solve it
 
  • #7
Can you name what type of equation that is?
 
  • #8
well I am on the section maximum and minum values, it doesn't say what kind of equation it is, id say its a critical number equation
 
  • #9
well I am on the section maximum and minum values, it doesn't say what kind of equation it is, id say its a critical number equation

:confused: :confused:

Just look at its form. It's a QUADRATIC equation! Have you not learned about those before? There's a formula for finding the roots of a quadratic equation. If you don't know it, look it up.
 
  • #10
ok, so when i take the derivative, i just factor it out
 
  • #11
afcwestwarrior said:
ok, so when i take the derivative, i just factor it out

What?? I don't understand what you mean by that.
 
  • #12
well I've learned about quadratic equations but i forgot what it was called,
well when i factored it out, i got 3(x^2+2x-8) then i factored it out

3(x+2)(x-4) ok that's easy, i forgot about that algebra stuff and trig and geo, like my calculus teacher said, it's not the calculus its all that old stuff that will get ya
 
  • #13
i mean 3 (x-2) (x+4)
 
  • #14
afcwestwarrior said:
i mean 3 (x-2) (x+4)

OK that's better I was just going to point that mistake out.
 
  • #15
yea hey thanks for reminding me about that,
 
  • #16
No problem. But I would recommend looking up the quadratic formula and remembering it. It works for those times when factoring isn't obvious.
 

What is a critical numbers problem?

A critical numbers problem is a mathematical problem that involves finding the points at which the derivative of a function is equal to zero. These points are called critical numbers and are important in finding the maximum and minimum values of a function.

How do you find critical numbers?

To find the critical numbers of a function, you must first take the derivative of the function and set it equal to zero. Then, solve for the variable to find the values of x that make the derivative equal to zero. These values are the critical numbers.

Why are critical numbers important?

Critical numbers are important because they help us find the maximum and minimum values of a function. These values are crucial in many real-world applications, such as optimization problems, where we want to find the most efficient solution.

Can there be more than one critical number?

Yes, there can be more than one critical number for a given function. This is because a function can have multiple points where its derivative is equal to zero, resulting in multiple critical numbers.

How do critical numbers relate to the graph of a function?

The critical numbers of a function are the x-values of the points where the function's graph changes direction. This means that the graph will have a maximum or minimum value at these points.

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