- #1
afcwestwarrior
- 457
- 0
g(T)=5^2/3+ t^5/3
g't= 10/3T^-1/3+ 5/3t^2/3
ok do i factor this one out, this one looks confusing
g't= 10/3T^-1/3+ 5/3t^2/3
ok do i factor this one out, this one looks confusing
I assume you meant g(T)= 6T^(2/3)+ T^(5/3).afcwestwarrior said:g(T)=5^2/3+ t^5/3
g't= 10/3T^-1/3+ 5/3t^2/3
ok do i factor this one out, this one looks confusing
A critical number is a value in a function where the derivative is either equal to zero or does not exist. It is important because it helps us determine the maximum and minimum values of a function.
To find critical numbers, you first need to find the derivative of the function. Then, set the derivative equal to zero and solve for the variable. Any values that satisfy this equation are considered critical numbers.
Critical numbers are important because they help us determine the behavior of a function. They can help us find the maximum and minimum values, as well as identify points of inflection.
Yes, a function can have multiple critical numbers. This can happen when the derivative is equal to zero at multiple points or when it does not exist at multiple points.
Critical numbers are used in real-life applications such as optimization problems in economics, engineering, and physics. They can also be used to analyze the behavior of a system in order to make predictions and improve performance.