- #1
likephysics
- 636
- 2
I was reading div grad curl and all that. Couldn't get something basic - cross product.
U = iux + k df/dx (ux)
V = jvy + k df/dy (vy)
UxV = [ -i df/dx - j df/dy + k] uxvy
can't figure out how to get U x V.
U = iux + k df/dx (ux)
V = jvy + k df/dy (vy)
UxV = [ -i df/dx - j df/dy + k] uxvy
can't figure out how to get U x V.