megatronic said:thanx MATLABdude, you are right the cable should be chosen by considering the load and the current carried to the load.
however what I meant is the maximum current appropriate for this size of cable.
stewartcs said:Is 25 mm the diameter or do you mean 25 mm^2 for the cross-sectional area?
CS
The current (I) is directly proportional to the cable size and voltage. This means that as the cable size increases, the current also increases, and as the voltage increases, the current also increases.
The formula for calculating current (I) is I = P/V, where P is the power and V is the voltage. With a 25 mm cable size and 480V, the formula becomes I = P/480.
The power (P) can be determined by using the formula P = VI, where V is the voltage and I is the current. In this case, the voltage is known (480V) and the current is what we are trying to calculate, so rearranging the formula gives us P = VI.
No, there is no standard value for the current (I) as it depends on the specific electrical system and its requirements. The calculated value will vary based on the power demand and other factors.
Yes, there are other factors that can affect the accuracy of the calculated current (I), such as the type of cable insulation, ambient temperature, and cable length. It is important to consider these factors when calculating the current (I) for a specific application.