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Regarding mathematical operators...

 
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Dec25-12, 05:30 AM   #18
 
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Regarding mathematical operators...

Quote by symbolipoint View Post
Maybe I misunderstood something. BA is not always equal to AB, but I made my comment in regard to product being the identity matrix I. Plenty enough for me to both learn and relearn about Linear Algebra.
Yea, it's true that [itex]AB\neq BA[/itex] in general. But if [itex]AB=I[/itex], then it can be proven that [itex]BA=AB=I[/itex]. This follows essentially from the rank-nullity theorem.
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