How Does Water Pressure Affect Buoyancy in Different Submerged Objects?

[alibaba2]

hi, I'm stuck on a homework task I've been given..help will be greatly appreciated

image link: img168.imageshack.us/my.php?image=image1vn3.jpg

setup is as follows:
image 1 . a tube (1ft diameter) submerged in water. tube is filled with air-filled balls( 1ft diameter) which tightly fit all the way in the tube, leaving only small water pockets in between.

image 2. same tube. solid object , no water gaps.

at 10ft depth, what would be the pressure that will have to be exerted on the uppermost ball in order to push the first ball out of the tube . i can't understand the buoyancy issue...??will it be equal to the sum of the buoyancy forces of all the balls?or will it be the pressure (kg/cm2) at a depth of 10ft. ...bit of a mess:)

what will be the difference if the shape was like that in image2? i want to calculate what would be the force to push the object 1ft deeper into the water outside the tube??

thank you

 

[alibaba2]

anybody??

ANybody?

 

[Moetasim]

for your question. It seems like you have a very interesting and challenging homework task. Let me try to break down the problem and provide some guidance.

Firstly, let's talk about the concept of buoyancy. Buoyancy is the upward force exerted by a fluid on an object immersed in it. This force is equal to the weight of the fluid displaced by the object. In your setup, the air-filled balls are lighter than the water, so they experience an upward buoyant force. This force will be equal to the weight of the water that is displaced by the balls.

Now, let's consider the first image. At a depth of 10ft, the pressure exerted by the water on the uppermost ball will be equal to the pressure at that depth. This pressure will be exerted on all the balls in the tube, including the one at the top. In order to push the first ball out of the tube, you will need to exert a force that is greater than the sum of the buoyant forces acting on all the balls. This force will need to overcome the buoyant force and the pressure exerted by the water.

In the second image, where there are no water gaps, the force required to push the object 1ft deeper into the water will be equal to the weight of the object. This force will need to overcome the buoyant force and the pressure exerted by the water.

In both cases, the shape of the object does not affect the calculation of the force required. It will only affect the distribution of the buoyant force.

I hope this helps to clarify the concept of buoyancy and how it applies to your setup. Good luck with your homework!