- #1
PhysicslyDSBL
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Homework Statement
A bullet of mass 0.0022 kg initially moving at 504 m/s embeds itself in a large fixed piece of wood and travels 0.72 m before coming to rest. Assume that the acceleration of the bullet is constant.
What force is exerted by the wood on the bullet?
F=N
Homework Equations
Ok, so I need to find acceleration to plug into the equation for force, which is F=m*a. The equation I am using is x=x0 + v0*t + .5*a*t^2.
The Attempt at a Solution
x=x0 + v0*t + .5*a*t^2 so this equation need to be set to solve for a. This is what I am plugging in:
x0 = 0
v0 = 504
t = 0.0014 (from d/s = t)
My answer is a = 0.706
The equation vf^2 = v0^2 + 2a (delta x), and set to solve for a but I am a bit confused about delta x? In this equation, vf = 0.72 and v0 = 504
I am either having trouble setting up the first equation for a, or I am using the wrong one in which case, I am not sure by what is meant by delta x in the second. Some direction is appreciated!