Question about law of reflection

[sachin123]

When is the law "the image is formed back in the mirror at a distance equal to that of the object from the mirror applicable?

Consider a plane mirror,with a glass slab on it.
Let an object be placed in front of it outside the slab, in air.
Now due to normal shift the mirror will see the object at a distance greater than the actual distance.Now should we use object distance =image distance with this distance,or...

an observer standing near object will see the mirror at a distance closer than it actually is.
Now,should we use object distance = image distance with this distance?

Can someone clear this out for me?I have to use this concept for many problems.
Or how at all should I do problems like this?
Thank You.

 

[cupid.callin]

Consider a plane mirror,with a glass slab on it.
Let an object be placed in front of it outside the slab, in air.
Now due to normal shift the mirror will see the object at a distance greater than the actual distance.Now should we use object distance =image distance with this distance,or...

it will be lesser distance because mostly slabs are denser than air ... it will be greater if slab is rarer than original material (i assumed it to be air)

an observer standing near object will see the mirror at a distance closer than it actually is.
Now,should we use object distance = image distance with this distance?

for mirror both object and image will be at equal distance but for object ... distance from image will not be twice of its distance from mirror

Let original distance is d and shift is x

so object distance from mirror is d-x and also image distance is d-x.

 

[sachin123]

Hey.
So you're saying that we must keep an observer near the mirror and then view the object,and find object distance and blindly use u=v?

Are you sure?
I have heard people argue that that can't be done as the rays after reflection will further get refracted at the slab air interface and this is completely ignored by the method suggested by you.Am i right?

 

[cupid.callin]

the image distance in this kind of questions depends on where is the observer

if observer is b/w mirror and slab then second refraction will have no effect
if he is on left of slab ie towards object then you must consider second refraction

 

[rwisz]

The law of reflection states that the angle of incidence is equal to the angle of reflection. This law applies to all types of reflection, including reflection from a mirror. In the scenario described, the image will always appear at a distance equal to that of the object from the mirror, regardless of the presence of a glass slab or the observer's position.

When the object is placed outside the glass slab, the image will appear at a distance equal to the actual distance of the object from the mirror. This is because the glass slab does not affect the reflection of light, it only shifts the position of the mirror.

Similarly, when the observer is standing near the object, the image will still appear at a distance equal to the actual distance of the object from the mirror. This is because the observer's position does not change the angle of reflection, only their perspective of the image.

In terms of problem-solving, it is important to understand the concept of the law of reflection and how it applies to different scenarios. For example, when solving problems involving reflection in a plane mirror, you can simply use the law of reflection to determine the location of the image. However, if the problem involves multiple reflections or the use of curved mirrors, more complex calculations may be necessary.

In summary, the law of reflection is always applicable when dealing with reflection from a mirror, regardless of the presence of a glass slab or the observer's position. Understanding this concept is crucial for solving problems involving reflection accurately.